Sort Colors

发布时间:2014-10-22 19:32:00编辑 分享查询网我要评论
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Given an array with n objects colored red, white or blue, sort them so that objects of the same color are adjacent, with the colors in the order red, white and blue. Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively. Note: You are not suppose to use the library's sort function for this problem. Follow up: A rather straight forward solution is a two-pass algorithm using counting sort. First, iterate the array counting number of 0's, 1's, and 2's, then overwrite array with total number of 0's, then 1's and followed by 2's. Could you come up with an one-pass algorithm using only constant space? 首先计算0,1,2出现的个数,然后据此重新填充数组。 void sortColors(int A[], int n) { vector<int> colorNum(3, 0); for(int i = 0; i < n; i++) colorNum[A[i]]++; int m = 0; for(int i = 0; i < 3; i++) { for(int j = 0; j < colorNum[i]; j++) { A[m++] = i; } } }

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关键词: Sort Colors