Message Flood

发布时间:2017-1-23 16:33:47 编辑 分享查询网我要评论
本篇文章主要介绍了"Message Flood",主要涉及到Message Flood方面的内容,对于Message Flood感兴趣的同学可以参考一下。

题目描述 Well, how do you feel about mobile phone? Your answer would probably be something like that "It's so convenient and benefits people a lot". However, If you ask Merlin this question on the New Year's Eve, he will definitely answer "What a trouble! I have to keep my fingers moving on the phone the whole night, because I have so many greeting message to send!" Yes, Merlin has such a long name list of his friends, and he would like to send a greeting message to each of them. What's worse, Merlin has another long name list of senders that have sent message to him, and he doesn't want to send another message to bother them Merlin is so polite that he always replies each message he receives immediately). So, before he begins to send message, he needs to figure to how many friends are left to be sent. Please write a program to help him. Here is something that you should note. First, Merlin's friend list is not ordered, and each name is alphabetic strings and case insensitive. These names are guaranteed to be not duplicated. Second, some senders may send more than one message to Merlin, therefore the sender list may be duplicated. Third, Merlin is known by so many people, that's why some message senders are even not included in his friend list. 输入 There are multiple test cases. In each case, at the first line there are two numbers n and m (1<=n,m<=20000), which is the number of friends and the number of messages he has received. And then there are n lines of alphabetic strings(the length of each will be less than 10), indicating the names of Merlin's friends, one per line. After that there are m lines of alphabetic strings, which are the names of message senders. The input is terminated by n=0. 输出 For each case, print one integer in one line which indicates the number of left friends he must send. 示例输入 5 3 Inkfish Henry Carp Max Jericho Carp Max Carp 0 示例输出 3 下面是正确的代码但是对,只是建立树的变量不一样就对了 #include<stdio.h> #include <string.h> #include <stdlib.h> struct node { int flag; node *next[26]; }; node *newnode() { int i; node *p=new node; for(i=0; i<26; i++) { p->next[i]=NULL; } p->flag=0; return p; } void charu(node *root, char *s) { int i, k=strlen(s),t; node *p=root; for(i=0; i<k; i++) { if(s[i]>='A'&&s[i]<='Z') t=s[i]-'A'; else t=s[i]-'a'; if(p->next[t]==NULL) p->next[t]=newnode(); p=p->next[t]; } p->flag=1; } int seach(node *root, char *s) { node *p=root; int i, t, k=strlen(s); for(i=0; i<k; i++) { if(s[i]>='A'&&s[i]<='Z') t=s[i]-'A'; else t=s[i]-'a'; if(p->next[t]==NULL) return 0; p=p->next[t]; } if(p->flag) { p->flag=0; return 1; } return 0; } void del(struct node *p) { int i; for(i=0; i<26; i++) if(p->next[i]!=NULL) del(p->next[i]); free(p); p=NULL; } int main() { int n, i, j,k, m; char s[20001][20], s0[20]; struct node *p; while(scanf("%d",&n)!=EOF) { if(n==0) break; k=0; scanf("%d",&m); p=newnode(); for(i=0; i<n; i++) { scanf("%s",s[i]); } for(i=0; i<m; i++) { scanf("%s",s0); charu(p, s0); } for(i=0;i<n;i++) { j=seach(p,s[i]); if(j) k++; } printf("%d\n",n-k); del(p); } return 0; }下面是错误的代码因为建立数组的方向不一样就错了#include<stdio.h> #include<string.h> #include<malloc.h> #include<stdlib.h> struct node { int data; struct node *next[26]; }; node *newnode() { int i; node * p = new node; for(i = 0; i < 26; i++) { p->next[i] = NULL; } p->data=0; return p; } void creat(node *head,char *a) { int n,i,t; node* p=head; n=strlen(a); for(i=0;i<n;i++) { if(a[i]>='A'&&a[i]<='Z') t=a[i]-'A'; else t=a[i]-'a'; if(p->next[t]==NULL) p->next[t]=newnode(); p=p->next[t]; } p->data=1; } int serch(node *head,char *b) { node *q=head; int i,n,t; n=strlen(b); for(i=0;i<n;i++) { if(b[i]>='A'&&b[i]<='Z') b[i]= b[i]+32; t=b[i]-'a'; if(q->next[t]==NULL) return 0; q=q->next[t]; } if(q->data) { q->data=0; return 1; } else return 0; } void del(node *p) { int i; for(i=0; i<26; i++) if(p->next[i]!=NULL) del(p->next[i]); free(p); p=NULL; } int main() { int m,n,i,l,k; char pa[20005][21]; char s[21]; node *head; while(~scanf("%d",&m)&&m) { scanf("%d",&n); k=0; head=newnode(); for(i=0;i<m;i++) { scanf("%s",pa[i]); creat(head,pa[i]); } for(i=0;i<n;i++) { scanf("%s",s); l=serch(head,s); k+=l; } printf("%d\n",m-k); del(head); } return 0; }

上一篇:设置 Sublime Text 的 Python 开发环境
下一篇:使用.NET Reflector单步调试编译好的程序集


关键词: Message Flood