[模拟]All in All uva10340

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Problem E All in All Input: standard input Output: standard output Time Limit: 2 seconds Memory Limit: 32 MB You have devised a new encryption technique which encodes a message by inserting between its characters randomly generated strings in a clever way. Because of pending patent issues we will not discuss in detail how the strings are generated and inserted into the original message. To validate your method, however, it is necessary to write a program that checks if the message is really encoded in the final string. Given two strings s and t, you have to decide whether s is a subsequence of t, i.e. if you can remove characters from t such that the concatenation of the remaining characters is s. Input Specification The input contains several testcases. Each is specified by two strings s, t of alphanumeric ASCII characters separated by whitespace. Input is terminated by EOF. Output Specification For each test case output, if s is a subsequence of t. Sample Input sequence subsequence person compression VERDI vivaVittorioEmanueleReDiItalia caseDoesMatter CaseDoesMatter Sample Output Yes No Yes No Source: ULM Local Contest   题意:给你2个字串s,t,请你写一个程式判断是否s是t的子字串。 很水的一道题么了,直接模拟就行了。 #include<iostream> #include<string> using namespace std; int main() { string str1,str2; while(cin>>str1>>str2) { int i,k=0; for(i=0;i<str2.size();i++) { if(str2[i]==str1[k]) k++; } if(k==str1.size()) cout<<"Yes"<<endl; else cout<<"No"<<endl; } return 0; }

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